cal(IT)/(lb·°F) to J/(kg·°C) Converter



From cal(IT)/(lb·°F) to J/(kg·°C): 1 cal(IT)/(lb·°F) = 5.1279507818463 J/(kg·°C);

From J/(kg·°C) to cal(IT)/(lb·°F): 1 J/(kg·°C) = 0.195009672 cal(IT)/(lb·°F);

How to Convert Calorie (IT)/Pound/°F to Joule/Kilogram/°C?

As we know One cal(IT)/(lb·°F) is equal to 5.1279507818463 J/(kg·°C) (1 cal(IT)/(lb·°F) = 5.1279507818463 J/(kg·°C)).

To convert Calorie (IT)/Pound/°F to Joule/Kilogram/°C, multiply your cal(IT)/(lb·°F) figure by 5.1279507818463.

Example : convert 25 cal(IT)/(lb·°F) to J/(kg·°C):

25 cal(IT)/(lb·°F) = 25 × 5.1279507818463 J/(kg·°C) = J/(kg·°C)

To convert Joule/Kilogram/°C to Calorie (IT)/Pound/°F, divide your J/(kg·°C) figure by 5.1279507818463.

Example : convert 25 J/(kg·°C) to cal(IT)/(lb·°F):

25 J/(kg·°C) = 25 ÷ 5.1279507818463 cal(IT)/(lb·°F) = cal(IT)/(lb·°F)

How to Convert Joule/Kilogram/°C to Calorie (IT)/Pound/°F?

As we know One J/(kg·°C) is equal to 0.195009672 cal(IT)/(lb·°F) (1 J/(kg·°C) = 0.195009672 cal(IT)/(lb·°F)).

To convert Joule/Kilogram/°C to Calorie (IT)/Pound/°F, multiply your J/(kg·°C) figure by 0.195009672.

Example : convert 45 J/(kg·°C) to cal(IT)/(lb·°F):

45 J/(kg·°C) = 45 × 0.195009672 cal(IT)/(lb·°F) = cal(IT)/(lb·°F)

To convert Calorie (IT)/Pound/°F to Joule/Kilogram/°C, divide your cal(IT)/(lb·°F) figure by 0.195009672.

Example : convert 45 cal(IT)/(lb·°F) to J/(kg·°C):

45 cal(IT)/(lb·°F) = 45 ÷ 0.195009672 J/(kg·°C) = J/(kg·°C)

Popular Specific Heat Capacity Unit Conversions

Convert Calorie (IT)/Pound/°F or Joule/Kilogram/°C to Other Specific Heat Capacity Units

Calorie (IT)/Pound/°F Conversion Table
cal(IT)/(lb·°F) to J/(kg·K)1 cal(IT)/(lb·°F) = 5.1279507818463 J/(kg·K)
cal(IT)/(lb·°F) to J/(kg·°C)1 cal(IT)/(lb·°F) = 5.1279507818463 J/(kg·°C)
cal(IT)/(lb·°F) to J/(g·°C)1 cal(IT)/(lb·°F) = 0.0051279507818463 J/(g·°C)
cal(IT)/(lb·°F) to kJ/(kg·K)1 cal(IT)/(lb·°F) = 0.0051279507818463 kJ/(kg·K)
cal(IT)/(lb·°F) to kJ/(kg·°C)1 cal(IT)/(lb·°F) = 0.0051279507818463 kJ/(kg·°C)
cal(IT)/(lb·°F) to kJ/(g·°C)1 cal(IT)/(lb·°F) = 5.1279507818463E-6 kJ/(g·°C)
cal(IT)/(lb·°F) to cal(IT)/(g·°C)1 cal(IT)/(lb·°F) = 0.0012247905324409 cal(IT)/(g·°C)
cal(IT)/(lb·°F) to cal(IT)/(g·K)1 cal(IT)/(lb·°F) = 0.0012247905324409 cal(IT)/(g·K)
cal(IT)/(lb·°F) to cal(th)/(g·°C)1 cal(IT)/(lb·°F) = 0.001225611004566 cal(th)/(g·°C)
cal(IT)/(lb·°F) to cal(th)/(g·K)1 cal(IT)/(lb·°F) = 0.001225611004566 cal(th)/(g·K)
cal(IT)/(lb·°F) to kcal(IT)/(kg·°C)1 cal(IT)/(lb·°F) = 0.0012247905324409 kcal(IT)/(kg·°C)
cal(IT)/(lb·°F) to kcal(th)/(kg·°C)1 cal(IT)/(lb·°F) = 0.001225611004566 kcal(th)/(kg·°C)
cal(IT)/(lb·°F) to kcal(IT)/(kg·K)1 cal(IT)/(lb·°F) = 0.0012247905324409 kcal(IT)/(kg·K)
cal(IT)/(lb·°F) to kcal(th)/(kg·K)1 cal(IT)/(lb·°F) = 0.001225611004566 kcal(th)/(kg·K)
cal(IT)/(lb·°F) to kgf·m/(kg·K)1 cal(IT)/(lb·°F) = 0.52290545363309 kgf·m/(kg·K)
cal(IT)/(lb·°F) to kgf·m/(kg·°C)1 cal(IT)/(lb·°F) = 0.52290545363309 kgf·m/(kg·°C)
cal(IT)/(lb·°F) to kgf·m/(g·K)1 cal(IT)/(lb·°F) = 0.00052290739712644 kgf·m/(g·K)
cal(IT)/(lb·°F) to kgf·m/(g·°C)1 cal(IT)/(lb·°F) = 0.00052290739712644 kgf·m/(g·°C)
cal(IT)/(lb·°F) to lbf·ft/(lb·°R)1 cal(IT)/(lb·°F) = 0.95309393166919 lbf·ft/(lb·°R)
cal(IT)/(lb·°F) to lbf·ft/(lb·°F)1 cal(IT)/(lb·°F) = 0.95309393166919 lbf·ft/(lb·°F)
cal(IT)/(lb·°F) to Btu(IT)/(lb·°F)1 cal(IT)/(lb·°F) = 0.0012247905324409 Btu(IT)/(lb·°F)
cal(IT)/(lb·°F) to Btu(th)/(lb·°F)1 cal(IT)/(lb·°F) = 0.001225611004566 Btu(th)/(lb·°F)
cal(IT)/(lb·°F) to Btu(IT)/(lb·°R)1 cal(IT)/(lb·°F) = 0.0012247905324409 Btu(IT)/(lb·°R)
cal(IT)/(lb·°F) to Btu(th)/(lb·°R)1 cal(IT)/(lb·°F) = 0.001225611004566 Btu(th)/(lb·°R)
cal(IT)/(lb·°F) to cal(IT)/(lb·°R)1 cal(IT)/(lb·°F) = 1 cal(IT)/(lb·°R)
cal(IT)/(lb·°F) to kcal(IT)/(lb·°F)1 cal(IT)/(lb·°F) = 0.0010000016819679 kcal(IT)/(lb·°F)
Calorie (IT)/Pound/°F Conversion Table
cal(IT)/(lb·°F) to kcal(IT)/(lb·°R)1 cal(IT)/(lb·°F) = 0.0010000016819679 kcal(IT)/(lb·°R)
cal(IT)/(lb·°F) to cal(th)/(lb·°R)1 cal(IT)/(lb·°F) = 1.0006694642305 cal(th)/(lb·°R)
cal(IT)/(lb·°F) to cal(th)/(lb·°F)1 cal(IT)/(lb·°F) = 1.0006694642305 cal(th)/(lb·°F)
cal(IT)/(lb·°F) to kcal(th)/(lb·°F)1 cal(IT)/(lb·°F) = 0.0010006683155695 kcal(th)/(lb·°F)
cal(IT)/(lb·°F) to kcal(th)/(lb·°R)1 cal(IT)/(lb·°F) = 0.0010006683155695 kcal(th)/(lb·°R)
cal(IT)/(lb·°F) to J/(lb·°F)1 cal(IT)/(lb·°F) = 4.1867981809641 J/(lb·°F)
cal(IT)/(lb·°F) to J/(lb·°R)1 cal(IT)/(lb·°F) = 4.1867981809641 J/(lb·°R)
cal(IT)/(lb·°F) to kJ/(lb·°F)1 cal(IT)/(lb·°F) = 0.004186797463051 kJ/(lb·°F)
cal(IT)/(lb·°F) to kJ/(lb·°R)1 cal(IT)/(lb·°F) = 0.004186797463051 kJ/(lb·°R)
cal(IT)/(lb·°F) to cal(IT)/(oz·°R)1 cal(IT)/(lb·°F) = 0.062499997436025 cal(IT)/(oz·°R)
cal(IT)/(lb·°F) to cal(IT)/(oz·°F)1 cal(IT)/(lb·°F) = 0.062499997436025 cal(IT)/(oz·°F)
cal(IT)/(lb·°F) to kcal(IT)/(oz·°F)1 cal(IT)/(lb·°F) = 6.2560999538525E-5 kcal(IT)/(oz·°F)
cal(IT)/(lb·°F) to kcal(IT)/(oz·°R)1 cal(IT)/(lb·°F) = 6.2560999538525E-5 kcal(IT)/(oz·°R)
cal(IT)/(lb·°F) to cal(th)/(oz·°R)1 cal(IT)/(lb·°F) = 0.062541841514404 cal(th)/(oz·°R)
cal(IT)/(lb·°F) to cal(th)/(oz·°F)1 cal(IT)/(lb·°F) = 0.062541841514404 cal(th)/(oz·°F)
cal(IT)/(lb·°F) to kcal(th)/(oz·°F)1 cal(IT)/(lb·°F) = 6.2560999538525E-5 kcal(th)/(oz·°F)
cal(IT)/(lb·°F) to kcal(th)/(oz·°R)1 cal(IT)/(lb·°F) = 6.2560999538525E-5 kcal(th)/(oz·°R)
cal(IT)/(lb·°F) to J/(oz·°F)1 cal(IT)/(lb·°F) = 0.26167488759224 J/(oz·°F)
cal(IT)/(lb·°F) to J/(oz·°R)1 cal(IT)/(lb·°F) = 0.26167488759224 J/(oz·°R)
cal(IT)/(lb·°F) to kJ/(oz·°F)1 cal(IT)/(lb·°F) = 0.00026152548987416 kJ/(oz·°F)
cal(IT)/(lb·°F) to kJ/(oz·°R)1 cal(IT)/(lb·°F) = 0.00026152548987416 kJ/(oz·°R)
cal(IT)/(lb·°F) to Btu(IT)/(lb·°C)1 cal(IT)/(lb·°F) = 0.0022046239839837 Btu(IT)/(lb·°C)
cal(IT)/(lb·°F) to CHU/(lb·°C)1 cal(IT)/(lb·°F) = 0.0012247905324409 CHU/(lb·°C)
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FAQ

What is 9 Calorie (IT)/Pound/°F in Joule/Kilogram/°C?

J/(kg·°C). Since one cal(IT)/(lb·°F) equals 5.1279507818463 J/(kg·°C), 9 cal(IT)/(lb·°F) in J/(kg·°C) will be J/(kg·°C).

How many Joule/Kilogram/°C are in a Calorie (IT)/Pound/°F?

There are 5.1279507818463 J/(kg·°C) in one cal(IT)/(lb·°F). In turn, one J/(kg·°C) is equal to 0.195009672 cal(IT)/(lb·°F).

How many cal(IT)/(lb·°F) is equal to 1 J/(kg·°C)?

1 J/(kg·°C) is approximately equal to 0.195009672 cal(IT)/(lb·°F).

What is the cal(IT)/(lb·°F) value of 8 J/(kg·°C)?

The Calorie (IT)/Pound/°F value of 8 J/(kg·°C) is cal(IT)/(lb·°F). (i.e.,) 8 x 0.195009672 = cal(IT)/(lb·°F).

cal(IT)/(lb·°F) to J/(kg·°C) converter in batch


   

 

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